5y^2+y=3y-3

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Solution for 5y^2+y=3y-3 equation: 



5y^2+y=3y-3

We move all terms to the left:

5y^2+y-(3y-3)=0

We get rid of parentheses

5y^2+y-3y+3=0

We add all the numbers together, and all the variables

5y^2-2y+3=0

a = 5; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·5·3
Δ = -56
Delta is less than zero, so there is no solution for the equation

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